DYT/Tool/OpenSceneGraph-3.6.5/include/geos/planargraph/DirectedEdge.h

/**********************************************************************
 *
 * GEOS - Geometry Engine Open Source
 * http://geos.osgeo.org
 *
 * Copyright (C) 2001-2002 Vivid Solutions Inc.
 * Copyright (C) 2005-2006 Refractions Research Inc.
 *
 * This is free software; you can redistribute and/or modify it under
 * the terms of the GNU Lesser General Public Licence as published
 * by the Free Software Foundation.
 * See the COPYING file for more information.
 *
 **********************************************************************/

#pragma once

#include <geos/export.h>
#include <geos/planargraph/GraphComponent.h> // for inheritance
#include <geos/geom/Coordinate.h> // for composition

#include <vector> // for typedefs
#include <list> // for typedefs

// Forward declarations
namespace geos {
namespace planargraph {
class Edge;
class Node;
}
}

namespace geos {
namespace planargraph { // geos.planargraph

/**
 * \brief Represents a directed edge in a PlanarGraph.
 *
 * A DirectedEdge may or may not have a reference to a parent Edge
 * (some applications of planar graphs may not require explicit Edge
 * objects to be created). Usually a client using a PlanarGraph
 * will subclass DirectedEdge to add its own application-specific
 * data and methods.
 */
class GEOS_DLL DirectedEdge: public GraphComponent {

public:

    friend std::ostream& operator << (std::ostream&, const DirectedEdge&);

    typedef std::list<DirectedEdge*> NonConstList;
    typedef std::list<const DirectedEdge*> ConstList;
    typedef std::vector<DirectedEdge*> NonConstVect;

protected:
    Edge* parentEdge;
    Node* from;
    Node* to;
    geom::Coordinate p0, p1;
    DirectedEdge* sym;  // optional
    bool edgeDirection;
    int quadrant;
    double angle;
public:

    typedef std::vector<const DirectedEdge*> ConstVect;
    typedef std::vector<DirectedEdge*> Vect;

    /**
     * \brief
     * Returns a List containing the parent Edge (possibly null)
     * for each of the given DirectedEdges.
     *
     * @note Ownership of the returned vector is left to
     * the caller, see the equivalent function taking a vector
     * reference to avoid this.
     */
    static std::vector<Edge*>* toEdges(
        std::vector<DirectedEdge*>& dirEdges);

    /**
     * \brief
     * Add parent Edge (possibly null) of each of the given DirectedEdges
     * to the given parentEdges vector.
     *
     * @note Parents are pushed to the parentEdges vector, make sure
     * it is empty if index-based corrispondence is important.
     */
    static void toEdges(std::vector<DirectedEdge*>& dirEdges,
                        std::vector<Edge*>& parentEdges);

    /**
     * \brief Constructs a DirectedEdge connecting the `from`
     * node to the `to` node.
     *
     * @param newFrom `from` node
     * @param newTo `to` node
     * @param directionPt specifies this DirectedEdge's direction
     *                    (given by an imaginary line from the
     *                    `from` node to
     *                    `directionPt`)
     * @param newEdgeDirection whether this DirectedEdge's direction
     *                         is the same as or opposite to that of the
     *                         parent Edge (if any)
     */
    DirectedEdge(Node* newFrom, Node* newTo,
                 const geom::Coordinate& directionPt,
                 bool newEdgeDirection);

    /**
     * \brief Returns this DirectedEdge's parent Edge,
     * or null if it has none.
     */
    Edge* getEdge() const;

    /**
     * \brief Associates this DirectedEdge with an Edge
     * (possibly null, indicating no associated Edge).
     */
    void setEdge(Edge* newParentEdge);

    /**
     * \brief Returns 0, 1, 2, or 3, indicating the quadrant in which
     * this DirectedEdge's orientation lies.
     */
    int getQuadrant() const;

    /**
     * \brief Returns a point to which an imaginary line is drawn
     * from the from-node to specify this DirectedEdge's orientation.
     */
    const geom::Coordinate& getDirectionPt() const;

    /**
     * \brief Returns whether the direction of the parent Edge (if any)
     * is the same as that of this Directed Edge.
     */
    bool getEdgeDirection() const;

    /**
     * \brief Returns the node from which this DirectedEdge leaves.
     */
    Node* getFromNode() const;

    /**
     * \brief Returns the node to which this DirectedEdge goes.
     */
    Node* getToNode() const;

    /**
     * \brief
     * Returns the coordinate of the from-node.
     */
    geom::Coordinate& getCoordinate() const;

    /**
     * \brief
     * Returns the angle that the start of this DirectedEdge makes
     * with the positive x-axis, in radians.
     */
    double getAngle() const;

    /**
     * \brief
     * Returns the symmetric DirectedEdge -- the other DirectedEdge
     * associated with this DirectedEdge's parent Edge.
     */
    DirectedEdge* getSym() const;

    /**
     * \brief
     * Sets this DirectedEdge's symmetric DirectedEdge, which runs
     * in the opposite direction.
     */
    void setSym(DirectedEdge* newSym);

    /**
     * \brief
     * Returns 1 if this DirectedEdge has a greater angle with the
     * positive x-axis than b", 0 if the DirectedEdges are collinear,
     * and -1 otherwise.
     *
     * Using the obvious algorithm of simply computing the angle is
     * not robust, since the angle calculation is susceptible to roundoff.
     * A robust algorithm is:
     *
     * - first compare the quadrants.
     *   If the quadrants are different, it it
     *   trivial to determine which std::vector is "greater".
     * - if the vectors lie in the same quadrant, the robust
     *   Orientation::index(Coordinate, Coordinate, Coordinate)
     *   function can be used to decide the relative orientation of
     *   the vectors.
     *
     */
    int compareTo(const DirectedEdge* obj) const;

    /**
     * \brief
     * Returns 1 if this DirectedEdge has a greater angle with the
     * positive x-axis than b", 0 if the DirectedEdges are collinear,
     * and -1 otherwise.
     *
     * Using the obvious algorithm of simply computing the angle is
     * not robust, since the angle calculation is susceptible to roundoff.
     * A robust algorithm is:
     *
     * - first compare the quadrants.
     *   If the quadrants are different, it it trivial to determine
     *   which std::vector is "greater".
     * - if the vectors lie in the same quadrant, the robust
     *   Orientation::index(Coordinate, Coordinate, Coordinate)
     *   function can be used to decide the relative orientation of
     *   the vectors.
     *
     */
    int compareDirection(const DirectedEdge* e) const;

    /**
     * \brief
     * Prints a detailed string representation of this DirectedEdge
     * to the given PrintStream.
     */
    std::string print() const;

};

/// Strict Weak comparator function for containers
bool pdeLessThan(DirectedEdge* first, DirectedEdge* second);

/// Output operator
std::ostream& operator << (std::ostream&, const DirectedEdge&);


} // namespace geos::planargraph
} // namespace geos